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15a^2+37a+20=0
a = 15; b = 37; c = +20;
Δ = b2-4ac
Δ = 372-4·15·20
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-13}{2*15}=\frac{-50}{30} =-1+2/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+13}{2*15}=\frac{-24}{30} =-4/5 $
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